| Base | Representation |
|---|---|
| bin | 101111100011011100… |
| … | …1111011001011110000 |
| 3 | 100202121000021121212120 |
| 4 | 1133012321323023300 |
| 5 | 3133121024234300 |
| 6 | 114525222154240 |
| 7 | 10243442623263 |
| oct | 1370671731360 |
| 9 | 322530247776 |
| 10 | 102121321200 |
| 11 | 3a344907118 |
| 12 | 17960282980 |
| 13 | 98261541a2 |
| 14 | 4d2aa9acda |
| 15 | 29ca5b43a0 |
| hex | 17c6e7b2f0 |
102121321200 has 120 divisors (see below), whose sum is σ = 327305467776. Its totient is φ = 27217632000.
The previous prime is 102121321187. The next prime is 102121321213. The reversal of 102121321200 is 2123121201.
102121321200 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an interprime number because it is at equal distance from previous prime (102121321187) and next prime (102121321213).
It is a tau number, because it is divible by the number of its divisors (120).
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 102121321200.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2295165 + ... + 2339235.
Almost surely, 2102121321200 is an apocalyptic number.
102121321200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 102121321200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (163652733888).
102121321200 is an abundant number, since it is smaller than the sum of its proper divisors (225184146576).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
102121321200 is a wasteful number, since it uses less digits than its factorization.
102121321200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 46023 (or 46012 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 15.
Adding to 102121321200 its reverse (2123121201), we get a palindrome (104244442401).
The spelling of 102121321200 in words is "one hundred two billion, one hundred twenty-one million, three hundred twenty-one thousand, two hundred".
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