Base | Representation |
---|---|
bin | 1001011000010011010010… |
… | …1111001001011000111011 |
3 | 1100111220220202110211212210 |
4 | 2112010310233021120323 |
5 | 2322432212410032110 |
6 | 33533435011310203 |
7 | 2113045156153242 |
oct | 226046457113073 |
9 | 40456822424783 |
10 | 10313101252155 |
11 | 3316841881a39 |
12 | 11a68b88ab363 |
13 | 59a6a131a530 |
14 | 27922a235959 |
15 | 12d4028a4520 |
hex | 96134bc963b |
10313101252155 has 64 divisors (see below), whose sum is σ = 18714896202240. Its totient is φ = 4807592165376.
The previous prime is 10313101252147. The next prime is 10313101252211. The reversal of 10313101252155 is 55125210131301.
10313101252155 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 10313101252155 - 23 = 10313101252147 is a prime.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 6726267 + ... + 8115963.
It is an arithmetic number, because the mean of its divisors is an integer number (292420253160).
Almost surely, 210313101252155 is an apocalyptic number.
10313101252155 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
10313101252155 is a deficient number, since it is larger than the sum of its proper divisors (8401794950085).
10313101252155 is a wasteful number, since it uses less digits than its factorization.
10313101252155 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1391740.
The product of its (nonzero) digits is 4500, while the sum is 30.
Adding to 10313101252155 its reverse (55125210131301), we get a palindrome (65438311383456).
The spelling of 10313101252155 in words is "ten trillion, three hundred thirteen billion, one hundred one million, two hundred fifty-two thousand, one hundred fifty-five".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •