Base | Representation |
---|---|
bin | 110001000110011111… |
… | …0100111110011010100 |
3 | 101002011121022121122210 |
4 | 1202030332213303110 |
5 | 3211422234110200 |
6 | 120235052153420 |
7 | 10422003651132 |
oct | 1421476476324 |
9 | 332147277583 |
10 | 105444441300 |
11 | 4079a702470 |
12 | 18529168870 |
13 | 9c3576cb43 |
14 | 5164174752 |
15 | 2b221d2650 |
hex | 188cfa7cd4 |
105444441300 has 72 divisors (see below), whose sum is σ = 332821010592. Its totient is φ = 25562288000.
The previous prime is 105444441251. The next prime is 105444441313. The reversal of 105444441300 is 3144444501.
It is a super-2 number, since 2×1054444413002 (a number of 23 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 15973131 + ... + 15979730.
It is an arithmetic number, because the mean of its divisors is an integer number (4622514036).
Almost surely, 2105444441300 is an apocalyptic number.
105444441300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
105444441300 is an abundant number, since it is smaller than the sum of its proper divisors (227376569292).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
105444441300 is a wasteful number, since it uses less digits than its factorization.
105444441300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 31952889 (or 31952882 counting only the distinct ones).
The product of its (nonzero) digits is 15360, while the sum is 30.
Adding to 105444441300 its reverse (3144444501), we get a palindrome (108588885801).
The spelling of 105444441300 in words is "one hundred five billion, four hundred forty-four million, four hundred forty-one thousand, three hundred".
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