Base | Representation |
---|---|
bin | 1101001000001… |
… | …11001101011100 |
3 | 21200020011222100 |
4 | 12210013031130 |
5 | 211143130022 |
6 | 14532245100 |
7 | 2505042516 |
oct | 644071534 |
9 | 250204870 |
10 | 110130012 |
11 | 57190343 |
12 | 30a70790 |
13 | 19a7c5b5 |
14 | 108aabb6 |
15 | 9a061ac |
hex | 690735c |
110130012 has 36 divisors (see below), whose sum is σ = 294761376. Its totient is φ = 34550400.
The previous prime is 110130001. The next prime is 110130047. The reversal of 110130012 is 210031011.
It is a tau number, because it is divible by the number of its divisors (36).
It is a Harshad number since it is a multiple of its sum of digits (9).
It is a junction number, because it is equal to n+sod(n) for n = 110129976 and 110130003.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 89364 + ... + 90587.
It is an arithmetic number, because the mean of its divisors is an integer number (8187816).
Almost surely, 2110130012 is an apocalyptic number.
110130012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
110130012 is an abundant number, since it is smaller than the sum of its proper divisors (184631364).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
110130012 is a wasteful number, since it uses less digits than its factorization.
110130012 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 179978 (or 179973 counting only the distinct ones).
The product of its (nonzero) digits is 6, while the sum is 9.
The square root of 110130012 is about 10494.2847302710. The cubic root of 110130012 is about 479.3306817109.
Adding to 110130012 its reverse (210031011), we get a palindrome (320161023).
Subtracting 110130012 from its reverse (210031011), we obtain a palindrome (99900999).
It can be divided in two parts, 1101 and 30012, that added together give a palindrome (31113).
The spelling of 110130012 in words is "one hundred ten million, one hundred thirty thousand, twelve".
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