111100343343440 has 640 divisors, whose sum is σ = 317610294497280. Its totient is φ = 35617370112000.

The previous prime is 111100343343419. The next prime is 111100343343443. The reversal of 111100343343440 is 44343343001111.

It is a junction number, because it is equal to n+sod(n) for n = 111100343343397 and 111100343343406.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (111100343343443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 25464206699 + ... + 25464211061.

It is an arithmetic number, because the mean of its divisors is an integer number (496266085152).

Almost surely, 2^{111100343343440} is an apocalyptic number.

111100343343440 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 111100343343440, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (158805147248640).

111100343343440 is an abundant number, since it is smaller than the sum of its proper divisors (206509951153840).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111100343343440 is a wasteful number, since it uses less digits than its factorization.

111100343343440 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5411 (or 5405 counting only the distinct ones).

The product of its (nonzero) digits is 20736, while the sum is 32.

Adding to 111100343343440 its reverse (44343343001111), we get a palindrome (155443686344551).

The spelling of 111100343343440 in words is "one hundred eleven trillion, one hundred billion, three hundred forty-three million, three hundred forty-three thousand, four hundred forty".