111300140024320 has 80 divisors (see below), whose sum is σ = 287387128468440. Its totient is φ = 41095436304384.

The previous prime is 111300140024309. The next prime is 111300140024321. The reversal of 111300140024320 is 23420041003111.

It can be written as a sum of positive squares in 4 ways, for example, as 41947487449344 + 69352652574976 = 6476688^2 + 8327824^2 .

It is a tau number, because it is divible by the number of its divisors (80).

It is a junction number, because it is equal to n+sod(n) for n = 111300140024291 and 111300140024300.

It is not an unprimeable number, because it can be changed into a prime (111300140024321) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1672144305 + ... + 1672210864.

Almost surely, 2^{111300140024320} is an apocalyptic number.

111300140024320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

111300140024320 is an abundant number, since it is smaller than the sum of its proper divisors (176086988444120).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

111300140024320 is an equidigital number, since it uses as much as digits as its factorization.

111300140024320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3344355205 (or 3344355189 counting only the distinct ones).

The product of its (nonzero) digits is 576, while the sum is 22.

Adding to 111300140024320 its reverse (23420041003111), we get a palindrome (134720181027431).

The spelling of 111300140024320 in words is "one hundred eleven trillion, three hundred billion, one hundred forty million, twenty-four thousand, three hundred twenty".