11134130000 has 100 divisors (see below), whose sum is σ = 30808013280. Its totient is φ = 3817392000.

The previous prime is 11134129987. The next prime is 11134130003. The reversal of 11134130000 is 3143111.

11134130000 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (100).

It is a Harshad number since it is a multiple of its sum of digits (14).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11134130003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 9530 + ... + 149529.

Almost surely, 2^11134130000 is an apocalyptic number.

11134130000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 11134130000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15404006640).

11134130000 is an abundant number, since it is smaller than the sum of its proper divisors (19673883280).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11134130000 is an equidigital number, since it uses as much as digits as its factorization.

11134130000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 159094 (or 159073 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 14.

Adding to 11134130000 its reverse (3143111), we get a palindrome (11137273111).

The spelling of 11134130000 in words is "eleven billion, one hundred thirty-four million, one hundred thirty thousand".