Search a number
-
+
112122133200 = 2433527211217103
BaseRepresentation
bin110100001101011111…
…1111111101011010000
3101201101222120111212000
41220122333333223100
53314111231230300
6123301434234000
711046330256500
oct1503277775320
9351358514760
10112122133200
1143607026200
1219891585900
13a75b06711c
1455d8d91a00
152db3582c00
hex1a1afffad0

112122133200 has 2160 divisors, whose sum is σ = 545526334080. Its totient is φ = 21714739200.

The previous prime is 112122133169. The next prime is 112122133213. The reversal of 112122133200 is 2331221211.

112122133200 is a `hidden beast` number, since 1 + 121 + 221 + 3 + 320 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (2160).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 431 ways as a sum of consecutive naturals, for example, 1088564349 + ... + 1088564451.

It is an arithmetic number, because the mean of its divisors is an integer number (252558488).

Almost surely, 2112122133200 is an apocalyptic number.

112122133200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 112122133200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (272763167040).

112122133200 is an abundant number, since it is smaller than the sum of its proper divisors (433404200880).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

112122133200 is a wasteful number, since it uses less digits than its factorization.

112122133200 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 183 (or 148 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 18.

Adding to 112122133200 its reverse (2331221211), we get a palindrome (114453354411).

It can be divided in two parts, 11212 and 2133200, that added together give a palindrome (2144412).

The spelling of 112122133200 in words is "one hundred twelve billion, one hundred twenty-two million, one hundred thirty-three thousand, two hundred".