Base | Representation |
---|---|
bin | 1101010111100… |
… | …00100010011100 |
3 | 21211000000100020 |
4 | 12223300202130 |
5 | 212201244200 |
6 | 15043232140 |
7 | 2531061105 |
oct | 653604234 |
9 | 254000306 |
10 | 112134300 |
11 | 5832a183 |
12 | 31678650 |
13 | 1a301975 |
14 | 10c6d3ac |
15 | 9c9eea0 |
hex | 6af089c |
112134300 has 72 divisors (see below), whose sum is σ = 335655600. Its totient is φ = 28869120.
The previous prime is 112134277. The next prime is 112134301. The reversal of 112134300 is 3431211.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 112134300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (112134301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2256 + ... + 15144.
Almost surely, 2112134300 is an apocalyptic number.
112134300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 112134300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (167827800).
112134300 is an abundant number, since it is smaller than the sum of its proper divisors (223521300).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
112134300 is a wasteful number, since it uses less digits than its factorization.
112134300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 12935 (or 12928 counting only the distinct ones).
The product of its (nonzero) digits is 72, while the sum is 15.
The square root of 112134300 is about 10589.3484218813. The cubic root of 112134300 is about 482.2210437968.
Adding to 112134300 its reverse (3431211), we get a palindrome (115565511).
The spelling of 112134300 in words is "one hundred twelve million, one hundred thirty-four thousand, three hundred".
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