Base | Representation |
---|---|
bin | 10000011100011011101… |
… | …100101100110001011000 |
3 | 11000000211111200211121221 |
4 | 100130123230230301120 |
5 | 122003311010221100 |
6 | 2223044514341424 |
7 | 144433320606361 |
oct | 20343354546130 |
9 | 4000744624557 |
10 | 1130041101400 |
11 | 3a627a818122 |
12 | 16301458a874 |
13 | 82740831313 |
14 | 3c9a1170b68 |
15 | 1e5dcee801a |
hex | 1071bb2cc58 |
1130041101400 has 96 divisors (see below), whose sum is σ = 2746453858560. Its totient is φ = 431594599040.
The previous prime is 1130041101367. The next prime is 1130041101401. The reversal of 1130041101400 is 41011400311.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1130041101401) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 2371629 + ... + 2807971.
It is an arithmetic number, because the mean of its divisors is an integer number (28608894360).
Almost surely, 21130041101400 is an apocalyptic number.
1130041101400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 1130041101400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (1373226929280).
1130041101400 is an abundant number, since it is smaller than the sum of its proper divisors (1616412757160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1130041101400 is a wasteful number, since it uses less digits than its factorization.
1130041101400 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 436945 (or 436936 counting only the distinct ones).
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1130041101400 its reverse (41011400311), we get a palindrome (1171052501711).
It can be divided in two parts, 113004 and 1101400, that added together give a square (1214404 = 11022).
The spelling of 1130041101400 in words is "one trillion, one hundred thirty billion, forty-one million, one hundred one thousand, four hundred".
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