11303121414040 has 64 divisors (see below), whose sum is σ = 26547277685760. Its totient is φ = 4323122052480.

The previous prime is 11303121414037. The next prime is 11303121414043. The reversal of 11303121414040 is 4041412130311.

11303121414040 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is an interprime number because it is at equal distance from previous prime (11303121414037) and next prime (11303121414043).

It is a junction number, because it is equal to n+sod(n) for n = 11303121413996 and 11303121414014.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11303121414043) by changing a digit.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 366717 + ... + 4768723.

It is an arithmetic number, because the mean of its divisors is an integer number (414801213840).

Almost surely, 2^{11303121414040} is an apocalyptic number.

11303121414040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

11303121414040 is an abundant number, since it is smaller than the sum of its proper divisors (15244156271720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11303121414040 is a wasteful number, since it uses less digits than its factorization.

11303121414040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4404832 (or 4404828 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 11303121414040 its reverse (4041412130311), we get a palindrome (15344533544351).

The spelling of 11303121414040 in words is "eleven trillion, three hundred three billion, one hundred twenty-one million, four hundred fourteen thousand, forty".