Base | Representation |
---|---|
bin | 1010010010010110010000… |
… | …1101010011110110000000 |
3 | 1111001020221100111012210022 |
4 | 2210211210031103312000 |
5 | 2440302024001213440 |
6 | 40015521030353012 |
7 | 2245100344416611 |
oct | 244454415236600 |
9 | 44036840435708 |
10 | 11310330101120 |
11 | 3670758534066 |
12 | 13280267bb768 |
13 | 640737449c1b |
14 | 2b15cc607c08 |
15 | 14931abcdcb5 |
hex | a4964353d80 |
11310330101120 has 128 divisors (see below), whose sum is σ = 28631102853600. Its totient is φ = 4257734492160.
The previous prime is 11310330101101. The next prime is 11310330101123. The reversal of 11310330101120 is 2110103301311.
It is a tau number, because it is divible by the number of its divisors (128).
It is a super-2 number, since 2×113103301011202 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (17).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11310330101123) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 274362110 + ... + 274403330.
Almost surely, 211310330101120 is an apocalyptic number.
11310330101120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 11310330101120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (14315551426800).
11310330101120 is an abundant number, since it is smaller than the sum of its proper divisors (17320772752480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11310330101120 is a wasteful number, since it uses less digits than its factorization.
11310330101120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 66476 (or 66464 counting only the distinct ones).
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 11310330101120 its reverse (2110103301311), we get a palindrome (13420433402431).
The spelling of 11310330101120 in words is "eleven trillion, three hundred ten billion, three hundred thirty million, one hundred one thousand, one hundred twenty".
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