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113132312411300 = 225271312432122243
BaseRepresentation
bin11001101110010010101011…
…010010110011110010100100
3112211120100021100221222010222
4121232102223102303302210
5104312024433434130200
61040340133345303512
732554353110644130
oct3156225322636244
9484510240858128
10113132312411300
1133058165003916
1210831972634b98
134b1843caa52a0
141dd18c14823c0
15d12c6ecddd85
hex66e4ab4b3ca4

113132312411300 has 72 divisors (see below), whose sum is σ = 302150299018176. Its totient is φ = 35804512056960.

The previous prime is 113132312411297. The next prime is 113132312411309. The reversal of 113132312411300 is 3114213231311.

It is a super-2 number, since 2×1131323124113002 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (26).

It is a self number, because there is not a number n which added to its sum of digits gives 113132312411300.

It is not an unprimeable number, because it can be changed into a prime (113132312411309) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 6216052022 + ... + 6216070221.

It is an arithmetic number, because the mean of its divisors is an integer number (4196531930808).

Almost surely, 2113132312411300 is an apocalyptic number.

113132312411300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

113132312411300 is an abundant number, since it is smaller than the sum of its proper divisors (189017986606876).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

113132312411300 is a wasteful number, since it uses less digits than its factorization.

113132312411300 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 12432122277 (or 12432122270 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 26.

Adding to 113132312411300 its reverse (3114213231311), we get a palindrome (116246525642611).

The spelling of 113132312411300 in words is "one hundred thirteen trillion, one hundred thirty-two billion, three hundred twelve million, four hundred eleven thousand, three hundred".

Divisors: 1 2 4 5 7 10 13 14 20 25 26 28 35 50 52 65 70 91 100 130 140 175 182 260 325 350 364 455 650 700 910 1300 1820 2275 4550 9100 12432122243 24864244486 49728488972 62160611215 87024855701 124321222430 161617589159 174049711402 248642444860 310803056075 323235178318 348099422804 435124278505 621606112150 646470356636 808087945795 870248557010 1131323124113 1243212224300 1616175891590 1740497114020 2175621392525 2262646248226 3232351783180 4040439728975 4351242785050 4525292496452 5656615620565 8080879457950 8702485570100 11313231241130 16161758915900 22626462482260 28283078102825 56566156205650 113132312411300