| Base | Representation |
|---|---|
| bin | 110100101110111100… |
| … | …0110101110011000000 |
| 3 | 101211022012012002002220 |
| 4 | 1221131320311303000 |
| 5 | 3323411022044300 |
| 6 | 124005043011040 |
| 7 | 11116204635000 |
| oct | 1513570656300 |
| 9 | 354265162086 |
| 10 | 113244331200 |
| 11 | 44032522170 |
| 12 | 19b45369a80 |
| 13 | a8a96ba800 |
| 14 | 56a402c000 |
| 15 | 2e2bd50da0 |
| hex | 1a5de35cc0 |
113244331200 has 2016 divisors, whose sum is σ = 525655641600. Its totient is φ = 21134131200.
The previous prime is 113244331181. The next prime is 113244331217. The reversal of 113244331200 is 2133442311.
It is a happy number.
It is a super-3 number, since 3×1132443312003 (a number of 34 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 287 ways as a sum of consecutive naturals, for example, 3060657582 + ... + 3060657618.
Almost surely, 2113244331200 is an apocalyptic number.
113244331200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 113244331200, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (262827820800).
113244331200 is an abundant number, since it is smaller than the sum of its proper divisors (412411310400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
113244331200 is a wasteful number, since it uses less digits than its factorization.
113244331200 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 120 (or 78 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 113244331200 its reverse (2133442311), we get a palindrome (115377773511).
Subtracting from 113244331200 its reverse (2133442311), we obtain a square (111110888889 = 3333332).
It can be divided in two parts, 113244 and 331200, that added together give a palindrome (444444).
The spelling of 113244331200 in words is "one hundred thirteen billion, two hundred forty-four million, three hundred thirty-one thousand, two hundred".
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