Base | Representation |
---|---|
bin | 11001111011000101011111… |
… | …100011011111100011011000 |
3 | 112221200101122011100200101102 |
4 | 121323011133203133203120 |
5 | 104420431033030341440 |
6 | 1042252055321210532 |
7 | 33005026334152430 |
oct | 3173053743374330 |
9 | 487611564320342 |
10 | 114011510012120 |
11 | 33367012145276 |
12 | 10954240030a48 |
13 | 4b80315873846 |
14 | 2022287b912c0 |
15 | d2aa7ae01b15 |
hex | 67b15f8df8d8 |
114011510012120 has 128 divisors (see below), whose sum is σ = 306156435609600. Its totient is φ = 37361100327936.
The previous prime is 114011510012011. The next prime is 114011510012149. The reversal of 114011510012120 is 21210015110411.
It is a Harshad number since it is a multiple of its sum of digits (20).
It is a junction number, because it is equal to n+sod(n) for n = 114011510012092 and 114011510012101.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1433957 + ... + 15168363.
It is an arithmetic number, because the mean of its divisors is an integer number (2391847153200).
Almost surely, 2114011510012120 is an apocalyptic number.
114011510012120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 114011510012120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (153078217804800).
114011510012120 is an abundant number, since it is smaller than the sum of its proper divisors (192144925597480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
114011510012120 is a wasteful number, since it uses less digits than its factorization.
114011510012120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 13735737 (or 13735733 counting only the distinct ones).
The product of its (nonzero) digits is 80, while the sum is 20.
Adding to 114011510012120 its reverse (21210015110411), we get a palindrome (135221525122531).
The spelling of 114011510012120 in words is "one hundred fourteen trillion, eleven billion, five hundred ten million, twelve thousand, one hundred twenty".
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