Base | Representation |
---|---|
bin | 10101010010110100… |
… | …11001000100111011 |
3 | 1002111201201001200110 |
4 | 22221122121010323 |
5 | 141403120440210 |
6 | 5130223435403 |
7 | 553205055414 |
oct | 125132310473 |
9 | 32451631613 |
10 | 11432202555 |
11 | 49371a8a94 |
12 | 2270755b63 |
13 | 11026325c7 |
14 | 7a645880b |
15 | 46d9b4420 |
hex | 2a969913b |
11432202555 has 64 divisors (see below), whose sum is σ = 19778411520. Its totient is φ = 5624526336.
The previous prime is 11432202553. The next prime is 11432202559. The reversal of 11432202555 is 55520223411.
11432202555 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is not a de Polignac number, because 11432202555 - 21 = 11432202553 is a prime.
It is not an unprimeable number, because it can be changed into a prime (11432202553) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1073517 + ... + 1084113.
It is an arithmetic number, because the mean of its divisors is an integer number (309037680).
Almost surely, 211432202555 is an apocalyptic number.
11432202555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11432202555 is a deficient number, since it is larger than the sum of its proper divisors (8346208965).
11432202555 is a wasteful number, since it uses less digits than its factorization.
11432202555 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 10740.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 11432202555 its reverse (55520223411), we get a palindrome (66952425966).
The spelling of 11432202555 in words is "eleven billion, four hundred thirty-two million, two hundred two thousand, five hundred fifty-five".
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