Base | Representation |
---|---|
bin | 11011010010001111101111… |
… | …100110000000011110111100 |
3 | 120201212222211202022201211101 |
4 | 123102033233212000132330 |
5 | 111212044233404013040 |
6 | 1103115425505302444 |
7 | 34163536253426164 |
oct | 3322175746003674 |
9 | 521788752281741 |
10 | 120001111001020 |
11 | 35266204812777 |
12 | 11561029334a24 |
13 | 51c609665ca22 |
14 | 218c1288335a4 |
15 | dd1786e6109a |
hex | 6d23ef9807bc |
120001111001020 has 72 divisors (see below), whose sum is σ = 263456163552960. Its totient is φ = 45909837747840.
The previous prime is 120001111001003. The next prime is 120001111001029. The reversal of 120001111001020 is 20100111100021.
It is a Harshad number since it is a multiple of its sum of digits (10).
It is a junction number, because it is equal to n+sod(n) for n = 120001111000988 and 120001111001006.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (120001111001029) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 135288765 + ... + 136172875.
It is an arithmetic number, because the mean of its divisors is an integer number (3659113382680).
Almost surely, 2120001111001020 is an apocalyptic number.
120001111001020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 120001111001020, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (131728081776480).
120001111001020 is an abundant number, since it is smaller than the sum of its proper divisors (143455052551940).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120001111001020 is a wasteful number, since it uses less digits than its factorization.
120001111001020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 896995 (or 896970 counting only the distinct ones).
The product of its (nonzero) digits is 4, while the sum is 10.
Adding to 120001111001020 its reverse (20100111100021), we get a palindrome (140101222101041).
Subtracting from 120001111001020 its reverse (20100111100021), we obtain a palindrome (99900999900999).
The spelling of 120001111001020 in words is "one hundred twenty trillion, one billion, one hundred eleven million, one thousand, twenty".
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