Base | Representation |
---|---|
bin | 10001011110101101110… |
… | …101010010011111100010 |
3 | 11020211112112212111111210 |
4 | 101132231311102133202 |
5 | 124140040322201310 |
6 | 2315455044250550 |
7 | 152533106053044 |
oct | 21365565223742 |
9 | 4224475774453 |
10 | 1201212303330 |
11 | 423482036576 |
12 | 1749776a0a56 |
13 | 893737c9260 |
14 | 421d353ba94 |
15 | 213a6356820 |
hex | 117add527e2 |
1201212303330 has 32 divisors (see below), whose sum is σ = 3104671800384. Its totient is φ = 295683028416.
The previous prime is 1201212303289. The next prime is 1201212303367. The reversal of 1201212303330 is 333032121021.
It is a junction number, because it is equal to n+sod(n) for n = 1201212303297 and 1201212303306.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 1540015384 + ... + 1540016163.
It is an arithmetic number, because the mean of its divisors is an integer number (97020993762).
Almost surely, 21201212303330 is an apocalyptic number.
1201212303330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1201212303330 is an abundant number, since it is smaller than the sum of its proper divisors (1903459497054).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1201212303330 is a wasteful number, since it uses less digits than its factorization.
1201212303330 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 3080031570.
The product of its (nonzero) digits is 648, while the sum is 21.
Adding to 1201212303330 its reverse (333032121021), we get a palindrome (1534244424351).
The spelling of 1201212303330 in words is "one trillion, two hundred one billion, two hundred twelve million, three hundred three thousand, three hundred thirty".
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