Base | Representation |
---|---|
bin | 1010111011101010110010… |
… | …0011011000010101000111 |
3 | 1120120010021100020202110210 |
4 | 2232322230203120111013 |
5 | 3033414344120400210 |
6 | 41322002042250503 |
7 | 2350301044342536 |
oct | 256725443302507 |
9 | 46503240222423 |
10 | 12020213450055 |
11 | 3914820143028 |
12 | 14217211b6a33 |
13 | 692669380815 |
14 | 2d7ad238831d |
15 | 15ca177a0e20 |
hex | aeeac8d8547 |
12020213450055 has 32 divisors (see below), whose sum is σ = 20394463359168. Its totient is φ = 6024547584000.
The previous prime is 12020213450023. The next prime is 12020213450107. The reversal of 12020213450055 is 55005431202021.
It is not a de Polignac number, because 12020213450055 - 25 = 12020213450023 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 35488096 + ... + 35825205.
It is an arithmetic number, because the mean of its divisors is an integer number (637326979974).
Almost surely, 212020213450055 is an apocalyptic number.
12020213450055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
12020213450055 is a deficient number, since it is larger than the sum of its proper divisors (8374249909113).
12020213450055 is a wasteful number, since it uses less digits than its factorization.
12020213450055 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 71313987.
The product of its (nonzero) digits is 12000, while the sum is 30.
Adding to 12020213450055 its reverse (55005431202021), we get a palindrome (67025644652076).
The spelling of 12020213450055 in words is "twelve trillion, twenty billion, two hundred thirteen million, four hundred fifty thousand, fifty-five".
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