Base | Representation |
---|---|
bin | 11011010101001100000011… |
… | …110010001110111010101100 |
3 | 120202121022202120110101101011 |
4 | 123111030003302032322230 |
5 | 111223402341140304400 |
6 | 1103352350104355004 |
7 | 34214255105034445 |
oct | 3325140362167254 |
9 | 522538676411334 |
10 | 120203313213100 |
11 | 35333a36684457 |
12 | 1159425a475a64 |
13 | 520c17bca6370 |
14 | 2197c2b1aa2cc |
15 | dd6b6d8dc8ba |
hex | 6d5303c8eeac |
120203313213100 has 72 divisors (see below), whose sum is σ = 280907768686160. Its totient is φ = 44382466010880.
The previous prime is 120203313212977. The next prime is 120203313213103. The reversal of 120203313213100 is 1312313302021.
It is a super-2 number, since 2×1202033132131002 (a number of 29 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (120203313213103) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 335744986 + ... + 336102814.
Almost surely, 2120203313213100 is an apocalyptic number.
120203313213100 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
120203313213100 is an abundant number, since it is smaller than the sum of its proper divisors (160704455473060).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
120203313213100 is a wasteful number, since it uses less digits than its factorization.
120203313213100 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 616259 (or 616252 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 120203313213100 its reverse (1312313302021), we get a palindrome (121515626515121).
The spelling of 120203313213100 in words is "one hundred twenty trillion, two hundred three billion, three hundred thirteen million, two hundred thirteen thousand, one hundred".
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