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120211202112012 = 223211793842577743
BaseRepresentation
bin11011010101010011011001…
…111111111111101000001100
3120202122002010100210222020100
4123111103121333333220030
5111224020020220041022
61103400132555051100
734214654436415644
oct3325233177775014
9522562110728210
10120211202112012
1135337314768a20
12115958a0440a90
13520cb384b9b9b
142198378bd3524
15dd6e8128e1ac
hex6d54d9fffa0c

120211202112012 has 72 divisors (see below), whose sum is σ = 335687591715840. Its totient is φ = 35966527665120.

The previous prime is 120211202111981. The next prime is 120211202112017. The reversal of 120211202112012 is 210211202112021.

120211202112012 is a `hidden beast` number, since 1 + 20 + 211 + 20 + 211 + 201 + 2 = 666.

It is a super-2 number, since 2×1202112021120122 (a number of 29 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is not an unprimeable number, because it can be changed into a prime (120211202112017) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1921257588 + ... + 1921320155.

It is an arithmetic number, because the mean of its divisors is an integer number (4662327662720).

Almost surely, 2120211202112012 is an apocalyptic number.

120211202112012 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

120211202112012 is an abundant number, since it is smaller than the sum of its proper divisors (215476389603828).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

120211202112012 is a wasteful number, since it uses less digits than its factorization.

120211202112012 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3842577843 (or 3842577838 counting only the distinct ones).

The product of its (nonzero) digits is 64, while the sum is 18.

Adding to 120211202112012 its reverse (210211202112021), we get a palindrome (330422404224033).

Subtracting 120211202112012 from its reverse (210211202112021), we obtain a palindrome (90000000000009).

The spelling of 120211202112012 in words is "one hundred twenty trillion, two hundred eleven billion, two hundred two million, one hundred twelve thousand, twelve".

Divisors: 1 2 3 4 6 9 11 12 18 22 33 36 44 66 79 99 132 158 198 237 316 396 474 711 869 948 1422 1738 2607 2844 3476 5214 7821 10428 15642 31284 3842577743 7685155486 11527733229 15370310972 23055466458 34583199687 42268355173 46110932916 69166399374 84536710346 126805065519 138332798748 169073420692 253610131038 303563641697 380415196557 507220262076 607127283394 760830393114 910690925091 1214254566788 1521660786228 1821381850182 2732072775273 3339200058667 3642763700364 5464145550546 6678400117334 10017600176001 10928291101092 13356800234668 20035200352002 30052800528003 40070400704004 60105601056006 120211202112012