Base | Representation |
---|---|
bin | 10001100111000110001… |
… | …101000011011111100000 |
3 | 11021200202200201210211120 |
4 | 101213012031003133200 |
5 | 124312003021333440 |
6 | 2323544024212240 |
7 | 153302105541321 |
oct | 21470615033740 |
9 | 4250680653746 |
10 | 1210211121120 |
11 | 42727a69a571 |
12 | 17666930a080 |
13 | 8a178c54401 |
14 | 42808726448 |
15 | 2173139cdd0 |
hex | 119c63437e0 |
1210211121120 has 48 divisors (see below), whose sum is σ = 3812165033040. Its totient is φ = 322722965504.
The previous prime is 1210211121037. The next prime is 1210211121157. The reversal of 1210211121120 is 211211120121.
It is a happy number.
It is a tau number, because it is divible by the number of its divisors (48).
It is a super-2 number, since 2×12102111211202 (a number of 25 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (15).
It is a self number, because there is not a number n which added to its sum of digits gives 1210211121120.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1260636105 + ... + 1260637064.
It is an arithmetic number, because the mean of its divisors is an integer number (79420104855).
Almost surely, 21210211121120 is an apocalyptic number.
1210211121120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1210211121120 is an abundant number, since it is smaller than the sum of its proper divisors (2601953911920).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1210211121120 is a wasteful number, since it uses less digits than its factorization.
1210211121120 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 2521273187 (or 2521273179 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 15.
Adding to 1210211121120 its reverse (211211120121), we get a palindrome (1421422241241).
Subtracting from 1210211121120 its reverse (211211120121), we obtain a palindrome (999000000999).
It can be divided in two parts, 1210211 and 121120, that added together give a palindrome (1331331).
The spelling of 1210211121120 in words is "one trillion, two hundred ten billion, two hundred eleven million, one hundred twenty-one thousand, one hundred twenty".
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