Search a number
-
+
121135316306130 = 23257227468325693
BaseRepresentation
bin11011100010110000000011…
…011111111000100011010010
3120212220102102110201001001100
4123202300003133320203102
5111334140111433244010
61105344443541245230
734341511030440300
oct3342600337704322
9525812373631040
10121135316306130
1135663221077765
1211704a04403816
13527901bb156b9
1421cada2a5d270
15e0101a8172c0
hex6e2c037f88d2

121135316306130 has 72 divisors (see below), whose sum is σ = 366372528106572. Its totient is φ = 27688072297536.

The previous prime is 121135316306117. The next prime is 121135316306143. The reversal of 121135316306130 is 31603613531121.

121135316306130 is a `hidden beast` number, since 1 + 2 + 1 + 1 + 3 + 5 + 3 + 1 + 6 + 30 + 613 + 0 = 666.

It is an interprime number because it is at equal distance from previous prime (121135316306117) and next prime (121135316306143).

It can be written as a sum of positive squares in 2 ways, for example, as 115641181888281 + 5494134417849 = 10753659^2 + 2343957^2 .

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 13734158437 + ... + 13734167256.

Almost surely, 2121135316306130 is an apocalyptic number.

121135316306130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

121135316306130 is an abundant number, since it is smaller than the sum of its proper divisors (245237211800442).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121135316306130 is a wasteful number, since it uses less digits than its factorization.

121135316306130 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 27468325720 (or 27468325710 counting only the distinct ones).

The product of its (nonzero) digits is 29160, while the sum is 36.

Adding to 121135316306130 its reverse (31603613531121), we get a palindrome (152738929837251).

The spelling of 121135316306130 in words is "one hundred twenty-one trillion, one hundred thirty-five billion, three hundred sixteen million, three hundred six thousand, one hundred thirty".

Divisors: 1 2 3 5 6 7 9 10 14 15 18 21 30 35 42 45 49 63 70 90 98 105 126 147 210 245 294 315 441 490 630 735 882 1470 2205 4410 27468325693 54936651386 82404977079 137341628465 164809954158 192278279851 247214931237 274683256930 384556559702 412024885395 494429862474 576834839553 824049770790 961391399255 1153669679106 1236074656185 1345947958957 1730504518659 1922782798510 2472149312370 2691895917914 2884174197765 3461009037318 4037843876871 5768348395530 6729739794785 8075687753742 8652522593295 12113531630613 13459479589570 17305045186590 20189219384355 24227063261226 40378438768710 60567658153065 121135316306130