Base | Representation |
---|---|
bin | 1011000001101101100110… |
… | …1100100010011000011110 |
3 | 1120221001021220010002012100 |
4 | 2300123121230202120132 |
5 | 3042120023302242400 |
6 | 41441413420545530 |
7 | 2360635155654513 |
oct | 260333154423036 |
9 | 46831256102170 |
10 | 12124050040350 |
11 | 39548651a1206 |
12 | 143987b9b22a6 |
13 | 69c3a6999221 |
14 | 2dcb42b8330a |
15 | 160593733100 |
hex | b06d9b2261e |
12124050040350 has 108 divisors (see below), whose sum is σ = 34051086590976. Its totient is φ = 3092511253920.
The previous prime is 12124050040339. The next prime is 12124050040357. The reversal of 12124050040350 is 5304005042121.
12124050040350 is a `hidden beast` number, since 1 + 2 + 124 + 0 + 500 + 4 + 0 + 35 + 0 = 666.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (12124050040357) by changing a digit.
It is a polite number, since it can be written in 53 ways as a sum of consecutive naturals, for example, 25227294 + ... + 25703393.
Almost surely, 212124050040350 is an apocalyptic number.
12124050040350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
12124050040350 is an abundant number, since it is smaller than the sum of its proper divisors (21927036550626).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12124050040350 is a wasteful number, since it uses less digits than its factorization.
12124050040350 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 50930751 (or 50930720 counting only the distinct ones).
The product of its (nonzero) digits is 4800, while the sum is 27.
Adding to 12124050040350 its reverse (5304005042121), we get a palindrome (17428055082471).
The spelling of 12124050040350 in words is "twelve trillion, one hundred twenty-four billion, fifty million, forty thousand, three hundred fifty".
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