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121335310000 = 245479153589
BaseRepresentation
bin111000100000000100…
…1011110011010110000
3102121012001210101110101
41301000021132122300
53441443314410000
6131423552442144
711523542055322
oct1610011363260
9377161711411
10121335310000
114750468a303
121b622b49354
13b598a36228
145c30819612
15325231ce6a
hex1c4025e6b0

121335310000 has 100 divisors (see below), whose sum is σ = 297485399200. Its totient is φ = 47919456000.

The previous prime is 121335309983. The next prime is 121335310021. The reversal of 121335310000 is 13533121.

It is a tau number, because it is divible by the number of its divisors (100).

It is a super-2 number, since 2×1213353100002 (a number of 23 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 121335310000.

It is an unprimeable number.

It is a polite number, since it can be written in 19 ways as a sum of consecutive naturals, for example, 713206 + ... + 866794.

It is an arithmetic number, because the mean of its divisors is an integer number (2974853992).

Almost surely, 2121335310000 is an apocalyptic number.

121335310000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121335310000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (148742699600).

121335310000 is an abundant number, since it is smaller than the sum of its proper divisors (176150089200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121335310000 is an equidigital number, since it uses as much as digits as its factorization.

121335310000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 153696 (or 153675 counting only the distinct ones).

The product of its (nonzero) digits is 270, while the sum is 19.

Adding to 121335310000 its reverse (13533121), we get a palindrome (121348843121).

The spelling of 121335310000 in words is "one hundred twenty-one billion, three hundred thirty-five million, three hundred ten thousand".

Divisors: 1 2 4 5 8 10 16 20 25 40 50 79 80 100 125 158 200 250 316 395 400 500 625 632 790 1000 1250 1264 1580 1975 2000 2500 3160 3950 5000 6320 7900 9875 10000 15800 19750 31600 39500 49375 79000 98750 153589 158000 197500 307178 395000 614356 767945 790000 1228712 1535890 2457424 3071780 3839725 6143560 7679450 12133531 12287120 15358900 19198625 24267062 30717800 38397250 48534124 60667655 61435600 76794500 95993125 97068248 121335310 153589000 191986250 194136496 242670620 303338275 307178000 383972500 485341240 606676550 767945000 970682480 1213353100 1516691375 1535890000 2426706200 3033382750 4853412400 6066765500 7583456875 12133531000 15166913750 24267062000 30333827500 60667655000 121335310000