Base | Representation |
---|---|
bin | 10001101010111010111… |
… | …101010001101000011010 |
3 | 11022002100212102112010200 |
4 | 101222322331101220122 |
5 | 124343410223341100 |
6 | 2325503312123030 |
7 | 153505626421512 |
oct | 21527275215032 |
9 | 4262325375120 |
10 | 1214317402650 |
11 | 428a97575670 |
12 | 177414536476 |
13 | 8a6818a87b1 |
14 | 42ab7c24842 |
15 | 218c1b18e00 |
hex | 11abaf51a1a |
1214317402650 has 144 divisors (see below), whose sum is σ = 3768410288448. Its totient is φ = 277063488000.
The previous prime is 1214317402637. The next prime is 1214317402651. The reversal of 1214317402650 is 562047134121.
1214317402650 is a `hidden beast` number, since 1 + 214 + 31 + 7 + 402 + 6 + 5 + 0 = 666.
It is a super-3 number, since 3×12143174026503 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1214317402651) by changing a digit.
It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 7131046 + ... + 7299345.
It is an arithmetic number, because the mean of its divisors is an integer number (26169515892).
Almost surely, 21214317402650 is an apocalyptic number.
1214317402650 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
1214317402650 is an abundant number, since it is smaller than the sum of its proper divisors (2554092885798).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1214317402650 is a wasteful number, since it uses less digits than its factorization.
1214317402650 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 14430437 (or 14430429 counting only the distinct ones).
The product of its (nonzero) digits is 40320, while the sum is 36.
The spelling of 1214317402650 in words is "one trillion, two hundred fourteen billion, three hundred seventeen million, four hundred two thousand, six hundred fifty".
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