Base | Representation |
---|---|
bin | 1011000110110001101001… |
… | …1011011001001101100100 |
3 | 1121020100211001102202200220 |
4 | 2301230122123121031210 |
5 | 3100031200031130200 |
6 | 41545401111204340 |
7 | 2400134561266215 |
oct | 261543233311544 |
9 | 47210731382626 |
10 | 12211035411300 |
11 | 398874216a930 |
12 | 14526b70766b0 |
13 | 6a765a08441b |
14 | 30303554b40c |
15 | 1629850cb4a0 |
hex | b1b1a6d9364 |
12211035411300 has 144 divisors (see below), whose sum is σ = 40218227868672. Its totient is φ = 2831544425600.
The previous prime is 12211035411287. The next prime is 12211035411349. The reversal of 12211035411300 is 311453011221.
12211035411300 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 80365704 + ... + 80517503.
It is an arithmetic number, because the mean of its divisors is an integer number (279293249088).
Almost surely, 212211035411300 is an apocalyptic number.
12211035411300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12211035411300 is an abundant number, since it is smaller than the sum of its proper divisors (28007192457372).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12211035411300 is a wasteful number, since it uses less digits than its factorization.
12211035411300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 160883258 (or 160883251 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 24.
Adding to 12211035411300 its reverse (311453011221), we get a palindrome (12522488422521).
The spelling of 12211035411300 in words is "twelve trillion, two hundred eleven billion, thirty-five million, four hundred eleven thousand, three hundred".
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