Base | Representation |
---|---|
bin | 10001110101010010101… |
… | …100011001111000111111 |
3 | 11100011002221010002112220 |
4 | 101311102230121320333 |
5 | 130034211440121310 |
6 | 2334544303500423 |
7 | 154351604033103 |
oct | 21652254317077 |
9 | 4304087102486 |
10 | 1225453051455 |
11 | 432791333406 |
12 | 1796018b7713 |
13 | 8b737948ab9 |
14 | 43452b25903 |
15 | 21d24550670 |
hex | 11d52b19e3f |
1225453051455 has 64 divisors (see below), whose sum is σ = 2083236019200. Its totient is φ = 613005797376.
The previous prime is 1225453051441. The next prime is 1225453051463. The reversal of 1225453051455 is 5541503545221.
It is a happy number.
It is not a de Polignac number, because 1225453051455 - 217 = 1225452920383 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 215632044 + ... + 215637726.
It is an arithmetic number, because the mean of its divisors is an integer number (32550562800).
Almost surely, 21225453051455 is an apocalyptic number.
1225453051455 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
1225453051455 is a deficient number, since it is larger than the sum of its proper divisors (857782967745).
1225453051455 is a wasteful number, since it uses less digits than its factorization.
1225453051455 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 8480.
The product of its (nonzero) digits is 600000, while the sum is 42.
Adding to 1225453051455 its reverse (5541503545221), we get a palindrome (6766956596676).
The spelling of 1225453051455 in words is "one trillion, two hundred twenty-five billion, four hundred fifty-three million, fifty-one thousand, four hundred fifty-five".
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