Base | Representation |
---|---|
bin | 111001010001101100… |
… | …0001100000011010000 |
3 | 102202111002102001112020 |
4 | 1302203120030003100 |
5 | 4003401012030222 |
6 | 132301103131440 |
7 | 11613025460421 |
oct | 1624330140320 |
9 | 382432361466 |
10 | 123000111312 |
11 | 481893a1161 |
12 | 1ba085a3b80 |
13 | b7a290a470 |
14 | 5d4b97b648 |
15 | 32ed56c65c |
hex | 1ca360c0d0 |
123000111312 has 80 divisors (see below), whose sum is σ = 342926176320. Its totient is φ = 37765057536.
The previous prime is 123000111281. The next prime is 123000111317. The reversal of 123000111312 is 213111000321.
It is a happy number.
It is a super-2 number, since 2×1230001113122 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 123000111291 and 123000111300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (123000111317) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 80364 + ... + 502452.
It is an arithmetic number, because the mean of its divisors is an integer number (4286577204).
Almost surely, 2123000111312 is an apocalyptic number.
123000111312 is a gapful number since it is divisible by the number (12) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 123000111312, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (171463088160).
123000111312 is an abundant number, since it is smaller than the sum of its proper divisors (219926065008).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
123000111312 is a wasteful number, since it uses less digits than its factorization.
123000111312 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 422580 (or 422574 counting only the distinct ones).
The product of its (nonzero) digits is 36, while the sum is 15.
Adding to 123000111312 its reverse (213111000321), we get a palindrome (336111111633).
The spelling of 123000111312 in words is "one hundred twenty-three billion, one hundred eleven thousand, three hundred twelve".
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