12314441300 has 72 divisors (see below), whose sum is σ = 32336305344. Its totient is φ = 3973731840.

The previous prime is 12314441299. The next prime is 12314441309. The reversal of 12314441300 is 314441321.

It is a super-2 number, since 2×12314441300² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (12314441309) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 505514 + ... + 529313.

It is an arithmetic number, because the mean of its divisors is an integer number (449115352).

Almost surely, 2^12314441300 is an apocalyptic number.

12314441300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

12314441300 is an abundant number, since it is smaller than the sum of its proper divisors (20021864044).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12314441300 is a wasteful number, since it uses less digits than its factorization.

12314441300 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1034865 (or 1034858 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 23.

Adding to 12314441300 its reverse (314441321), we get a palindrome (12628882621).

The spelling of 12314441300 in words is "twelve billion, three hundred fourteen million, four hundred forty-one thousand, three hundred".