Base | Representation |
---|---|
bin | 1011011001011010111000… |
… | …1000010101011101000000 |
3 | 1122100222120200221202012002 |
4 | 2312112232020111131000 |
5 | 3120303141300214130 |
6 | 42352452452123132 |
7 | 2432234212130030 |
oct | 266265610253500 |
9 | 48328520852162 |
10 | 12531341023040 |
11 | 3aa156a352834 |
12 | 14a47a89064a8 |
13 | 6cb9149a1ab8 |
14 | 31473d3a98c0 |
15 | 16ae80272b45 |
hex | b65ae215740 |
12531341023040 has 112 divisors (see below), whose sum is σ = 34681169347200. Its totient is φ = 4223638382592.
The previous prime is 12531341023027. The next prime is 12531341023067. The reversal of 12531341023040 is 4032014313521.
It is a tau number, because it is divible by the number of its divisors (112).
It is a junction number, because it is equal to n+sod(n) for n = 12531341022994 and 12531341023012.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 47277575 + ... + 47541894.
Almost surely, 212531341023040 is an apocalyptic number.
12531341023040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
12531341023040 is an abundant number, since it is smaller than the sum of its proper divisors (22149828324160).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
12531341023040 is an equidigital number, since it uses as much as digits as its factorization.
12531341023040 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94819552 (or 94819542 counting only the distinct ones).
The product of its (nonzero) digits is 8640, while the sum is 29.
Adding to 12531341023040 its reverse (4032014313521), we get a palindrome (16563355336561).
The spelling of 12531341023040 in words is "twelve trillion, five hundred thirty-one billion, three hundred forty-one million, twenty-three thousand, forty".
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