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12993968332800 = 213335273131731
BaseRepresentation
bin1011110100010110010011…
…0111011110000000000000
31201000012200222212002101000
42331011210313132000000
53200343121343122200
643345202513012000
72510532435312000
oct275054467360000
951005628762330
1012993968332800
11415a79040a974
12155a399854000
13733431182880
1432cca8d32000
15178009d96300
hexbd164dde000

12993968332800 has 5376 divisors, whose sum is σ = 65527805952000. Its totient is φ = 2497078886400.

The previous prime is 12993968332799. The next prime is 12993968332811. The reversal of 12993968332800 is 823386939921.

12993968332800 is a `hidden beast` number, since 1 + 2 + 99 + 396 + 83 + 3 + 2 + 80 + 0 = 666.

It is a tau number, because it is divible by the number of its divisors (5376).

It is a super-3 number, since 3×129939683328003 (a number of 40 digits) contains 333 as substring.

It is a Harshad number since it is a multiple of its sum of digits (63).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 383 ways as a sum of consecutive naturals, for example, 419160268785 + ... + 419160268815.

It is an arithmetic number, because the mean of its divisors is an integer number (12188952000).

Almost surely, 212993968332800 is an apocalyptic number.

12993968332800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 12993968332800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (32763902976000).

12993968332800 is an abundant number, since it is smaller than the sum of its proper divisors (52533837619200).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

12993968332800 is a wasteful number, since it uses less digits than its factorization.

12993968332800 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 127 (or 78 counting only the distinct ones).

The product of its (nonzero) digits is 30233088, while the sum is 63.

The spelling of 12993968332800 in words is "twelve trillion, nine hundred ninety-three billion, nine hundred sixty-eight million, three hundred thirty-two thousand, eight hundred".