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13002112232320 = 27527174966053
BaseRepresentation
bin1011110100110100101001…
…0001111110101110000000
31201000222201120001001022011
42331031022101332232000
53201011311212413240
643353030553022304
72511241314313201
oct275151221765600
951028646031264
1013002112232320
11416318a433142
12155ba910b4994
1373412b469c23
1432d43c7775a8
15178334d186ea
hexbd34a47eb80

13002112232320 has 64 divisors (see below), whose sum is σ = 31197873032640. Its totient is φ = 5181653514240.

The previous prime is 13002112232309. The next prime is 13002112232327. The reversal of 13002112232320 is 2323221120031.

13002112232320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a tau number, because it is divible by the number of its divisors (64).

It is a junction number, because it is equal to n+sod(n) for n = 13002112232291 and 13002112232300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13002112232327) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37309587 + ... + 37656466.

It is an arithmetic number, because the mean of its divisors is an integer number (487466766135).

Almost surely, 213002112232320 is an apocalyptic number.

13002112232320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13002112232320 is an abundant number, since it is smaller than the sum of its proper divisors (18195760800320).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13002112232320 is an equidigital number, since it uses as much as digits as its factorization.

13002112232320 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 74966343 (or 74966331 counting only the distinct ones).

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 13002112232320 its reverse (2323221120031), we get a palindrome (15325333352351).

The spelling of 13002112232320 in words is "thirteen trillion, two billion, one hundred twelve million, two hundred thirty-two thousand, three hundred twenty".

Divisors: 1 2 4 5 8 10 16 20 32 40 64 80 128 160 271 320 542 640 1084 1355 2168 2710 4336 5420 8672 10840 17344 21680 34688 43360 86720 173440 74966053 149932106 299864212 374830265 599728424 749660530 1199456848 1499321060 2398913696 2998642120 4797827392 5997284240 9595654784 11994568480 20315800363 23989136960 40631600726 47978273920 81263201452 101579001815 162526402904 203158003630 325052805808 406316007260 650105611616 812632014520 1300211223232 1625264029040 2600422446464 3250528058080 6501056116160 13002112232320