Base | Representation |
---|---|
bin | 1011110100110100101001… |
… | …0001111110101110000000 |
3 | 1201000222201120001001022011 |
4 | 2331031022101332232000 |
5 | 3201011311212413240 |
6 | 43353030553022304 |
7 | 2511241314313201 |
oct | 275151221765600 |
9 | 51028646031264 |
10 | 13002112232320 |
11 | 416318a433142 |
12 | 155ba910b4994 |
13 | 73412b469c23 |
14 | 32d43c7775a8 |
15 | 178334d186ea |
hex | bd34a47eb80 |
13002112232320 has 64 divisors (see below), whose sum is σ = 31197873032640. Its totient is φ = 5181653514240.
The previous prime is 13002112232309. The next prime is 13002112232327. The reversal of 13002112232320 is 2323221120031.
13002112232320 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a tau number, because it is divible by the number of its divisors (64).
It is a junction number, because it is equal to n+sod(n) for n = 13002112232291 and 13002112232300.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (13002112232327) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 37309587 + ... + 37656466.
It is an arithmetic number, because the mean of its divisors is an integer number (487466766135).
Almost surely, 213002112232320 is an apocalyptic number.
13002112232320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13002112232320 is an abundant number, since it is smaller than the sum of its proper divisors (18195760800320).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13002112232320 is an equidigital number, since it uses as much as digits as its factorization.
13002112232320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 74966343 (or 74966331 counting only the distinct ones).
The product of its (nonzero) digits is 864, while the sum is 22.
Adding to 13002112232320 its reverse (2323221120031), we get a palindrome (15325333352351).
The spelling of 13002112232320 in words is "thirteen trillion, two billion, one hundred twelve million, two hundred thirty-two thousand, three hundred twenty".
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