13003331401040 has 80 divisors (see below), whose sum is σ = 32012036522640. Its totient is φ = 4895235072000.

The previous prime is 13003331401033. The next prime is 13003331401063. The reversal of 13003331401040 is 4010413330031.

It can be written as a sum of positive squares in 8 ways, for example, as 389980266256 + 12613351134784 = 624484^2 + 3551528^2 .

It is a tau number, because it is divible by the number of its divisors (80).

It is a junction number, because it is equal to n+sod(n) for n = 13003331400997 and 13003331401015.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 57808790 + ... + 58033290.

It is an arithmetic number, because the mean of its divisors is an integer number (400150456533).

Almost surely, 2^{13003331401040} is an apocalyptic number.

13003331401040 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13003331401040 is an abundant number, since it is smaller than the sum of its proper divisors (19008705121600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13003331401040 is a wasteful number, since it uses less digits than its factorization.

13003331401040 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 267120 (or 267114 counting only the distinct ones).

The product of its (nonzero) digits is 1296, while the sum is 23.

Adding to 13003331401040 its reverse (4010413330031), we get a palindrome (17013744731071).

The spelling of 13003331401040 in words is "thirteen trillion, three billion, three hundred thirty-one million, four hundred one thousand, forty".