Base | Representation |
---|---|
bin | 11101100100001110111110… |
… | …100100011010010010011100 |
3 | 122001102001202111020112012020 |
4 | 131210032332210122102130 |
5 | 114020431231004233200 |
6 | 1140320253232340140 |
7 | 36250412121665334 |
oct | 3544167644322234 |
9 | 561361674215166 |
10 | 130033332102300 |
11 | 38483910012010 |
12 | 127013b79a4650 |
13 | 577312408c443 |
14 | 241790ad7c0c4 |
15 | 10076ea9b6ea0 |
hex | 7643be91a49c |
130033332102300 has 72 divisors (see below), whose sum is σ = 410432480973312. Its totient is φ = 31523232024000.
The previous prime is 130033332102227. The next prime is 130033332102307. The reversal of 130033332102300 is 3201233330031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (130033332102307) by changing a digit.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 19702016716 + ... + 19702023315.
Almost surely, 2130033332102300 is an apocalyptic number.
130033332102300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
130033332102300 is an abundant number, since it is smaller than the sum of its proper divisors (280399148871012).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
130033332102300 is a wasteful number, since it uses less digits than its factorization.
130033332102300 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39404040059 (or 39404040052 counting only the distinct ones).
The product of its (nonzero) digits is 2916, while the sum is 24.
Adding to 130033332102300 its reverse (3201233330031), we get a palindrome (133234565432331).
The spelling of 130033332102300 in words is "one hundred thirty trillion, thirty-three billion, three hundred thirty-two million, one hundred two thousand, three hundred".
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