Base | Representation |
---|---|
bin | 10010111110011111101… |
… | …011101001110001011000 |
3 | 11121122222202212122110021 |
4 | 102332133223221301120 |
5 | 132331200323030240 |
6 | 2435024005200224 |
7 | 163133451025042 |
oct | 22763753516130 |
9 | 4548882778407 |
10 | 1304054111320 |
11 | 463056605014 |
12 | 190899100074 |
13 | 95c82cb368c |
14 | 4718bb86a92 |
15 | 23dc4cd854a |
hex | 12f9fae9c58 |
1304054111320 has 64 divisors (see below), whose sum is σ = 3062390353920. Its totient is φ = 498828680064.
The previous prime is 1304054111303. The next prime is 1304054111323. The reversal of 1304054111320 is 231114504031.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1304054111323) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 3931869 + ... + 4250611.
It is an arithmetic number, because the mean of its divisors is an integer number (47849849280).
Almost surely, 21304054111320 is an apocalyptic number.
1304054111320 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1304054111320 is an abundant number, since it is smaller than the sum of its proper divisors (1758336242600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1304054111320 is a wasteful number, since it uses less digits than its factorization.
1304054111320 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 323224 (or 323220 counting only the distinct ones).
The product of its (nonzero) digits is 1440, while the sum is 25.
Adding to 1304054111320 its reverse (231114504031), we get a palindrome (1535168615351).
The spelling of 1304054111320 in words is "one trillion, three hundred four billion, fifty-four million, one hundred eleven thousand, three hundred twenty".
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