Base | Representation |
---|---|
bin | 11000010010100011… |
… | …11010011001110100 |
3 | 1020122211011201220102 |
4 | 30021101322121310 |
5 | 203201342430000 |
6 | 5554001053232 |
7 | 641105131055 |
oct | 141121723164 |
9 | 36584151812 |
10 | 13040592500 |
11 | 5592090181 |
12 | 263b327218 |
13 | 12ca915130 |
14 | 8b9cd472c |
15 | 514cbe3d5 |
hex | 30947a674 |
13040592500 has 120 divisors (see below), whose sum is σ = 30834404832. Its totient is φ = 4795632000.
The previous prime is 13040592443. The next prime is 13040592533. The reversal of 13040592500 is 529504031.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 9976847 + ... + 9978153.
Almost surely, 213040592500 is an apocalyptic number.
13040592500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13040592500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15417202416).
13040592500 is an abundant number, since it is smaller than the sum of its proper divisors (17793812332).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13040592500 is a wasteful number, since it uses less digits than its factorization.
13040592500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1651 (or 1634 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 29.
The spelling of 13040592500 in words is "thirteen billion, forty million, five hundred ninety-two thousand, five hundred".
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