Base | Representation |
---|---|
bin | 1011110111111010110100… |
… | …1100011111000110000000 |
3 | 1201020002001002112221010210 |
4 | 2331332231030133012000 |
5 | 3202344234201002000 |
6 | 43433305514354120 |
7 | 2515133533306152 |
oct | 275765514370600 |
9 | 51202032487123 |
10 | 13055311344000 |
11 | 41837a99a2142 |
12 | 156a25942b940 |
13 | 739158c27033 |
14 | 331c47d00ad2 |
15 | 1798ea483350 |
hex | bdfad31f180 |
13055311344000 has 128 divisors (see below), whose sum is σ = 43278357264480. Its totient is φ = 3481416345600.
The previous prime is 13055311343993. The next prime is 13055311344013. The reversal of 13055311344000 is 44311355031.
It is a tau number, because it is divible by the number of its divisors (128).
It is a Harshad number since it is a multiple of its sum of digits (30).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 135944827 + ... + 136040826.
Almost surely, 213055311344000 is an apocalyptic number.
13055311344000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13055311344000 is an abundant number, since it is smaller than the sum of its proper divisors (30223045920480).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13055311344000 is an equidigital number, since it uses as much as digits as its factorization.
13055311344000 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 271985685 (or 271985663 counting only the distinct ones).
The product of its (nonzero) digits is 10800, while the sum is 30.
Adding to 13055311344000 its reverse (44311355031), we get a palindrome (13099622699031).
The spelling of 13055311344000 in words is "thirteen trillion, fifty-five billion, three hundred eleven million, three hundred forty-four thousand".
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