Base | Representation |
---|---|
bin | 10011000010001100010… |
… | …011111101100100000000 |
3 | 11122001020110010000122112 |
4 | 103002030103331210000 |
5 | 132412313132213440 |
6 | 2440521543554452 |
7 | 163334025261242 |
oct | 23021423754400 |
9 | 4561213100575 |
10 | 1308024101120 |
11 | 464803561120 |
12 | 19160675ba28 |
13 | 96466628579 |
14 | 47447128092 |
15 | 240585d1965 |
hex | 1308c4fd900 |
1308024101120 has 72 divisors (see below), whose sum is σ = 3417956196480. Its totient is φ = 475645122560.
The previous prime is 1308024101101. The next prime is 1308024101123. The reversal of 1308024101120 is 211014208031.
It is a super-2 number, since 2×13080241011202 (a number of 25 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (1308024101123) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 46435640 + ... + 46463799.
It is an arithmetic number, because the mean of its divisors is an integer number (47471613840).
Almost surely, 21308024101120 is an apocalyptic number.
1308024101120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1308024101120 is an abundant number, since it is smaller than the sum of its proper divisors (2109932095360).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1308024101120 is an equidigital number, since it uses as much as digits as its factorization.
1308024101120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 92899471 (or 92899457 counting only the distinct ones).
The product of its (nonzero) digits is 384, while the sum is 23.
Adding to 1308024101120 its reverse (211014208031), we get a palindrome (1519038309151).
The spelling of 1308024101120 in words is "one trillion, three hundred eight billion, twenty-four million, one hundred one thousand, one hundred twenty".
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