Base | Representation |
---|---|
bin | 1011111010100001011000… |
… | …0111000110101110101000 |
3 | 1201101100110000001122211100 |
4 | 2332220112013012232220 |
5 | 3204112320412322440 |
6 | 43510022222201400 |
7 | 2521305511033551 |
oct | 276502607065650 |
9 | 51340400048740 |
10 | 13100021214120 |
11 | 41a0762505325 |
12 | 1576a56723260 |
13 | 7404329b4a99 |
14 | 334089c09328 |
15 | 17ab656b2230 |
hex | bea161c6ba8 |
13100021214120 has 96 divisors (see below), whose sum is σ = 42684516880200. Its totient is φ = 3484358647296.
The previous prime is 13100021214107. The next prime is 13100021214143. The reversal of 13100021214120 is 2141212000131.
13100021214120 is a `hidden beast` number, since 1 + 310 + 0 + 0 + 21 + 214 + 120 = 666.
13100021214120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It can be written as a sum of positive squares in 4 ways, for example, as 11695127794596 + 1404893419524 = 3419814^2 + 1185282^2 .
It is a super-2 number, since 2×131000212141202 (a number of 27 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (18).
It is a junction number, because it is equal to n+sod(n) for n = 13100021214093 and 13100021214102.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 46632387 + ... + 46912466.
Almost surely, 213100021214120 is an apocalyptic number.
13100021214120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13100021214120 is an abundant number, since it is smaller than the sum of its proper divisors (29584495666080).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13100021214120 is a wasteful number, since it uses less digits than its factorization.
13100021214120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 93545259 (or 93545252 counting only the distinct ones).
The product of its (nonzero) digits is 96, while the sum is 18.
Adding to 13100021214120 its reverse (2141212000131), we get a palindrome (15241233214251).
The spelling of 13100021214120 in words is "thirteen trillion, one hundred billion, twenty-one million, two hundred fourteen thousand, one hundred twenty".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.076 sec. • engine limits •