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13100021214120 = 2332538993544853
BaseRepresentation
bin1011111010100001011000…
…0111000110101110101000
31201101100110000001122211100
42332220112013012232220
53204112320412322440
643510022222201400
72521305511033551
oct276502607065650
951340400048740
1013100021214120
1141a0762505325
121576a56723260
137404329b4a99
14334089c09328
1517ab656b2230
hexbea161c6ba8

13100021214120 has 96 divisors (see below), whose sum is σ = 42684516880200. Its totient is φ = 3484358647296.

The previous prime is 13100021214107. The next prime is 13100021214143. The reversal of 13100021214120 is 2141212000131.

13100021214120 is a `hidden beast` number, since 1 + 310 + 0 + 0 + 21 + 214 + 120 = 666.

13100021214120 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 4 ways, for example, as 11695127794596 + 1404893419524 = 3419814^2 + 1185282^2 .

It is a super-2 number, since 2×131000212141202 (a number of 27 digits) contains 22 as substring.

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a junction number, because it is equal to n+sod(n) for n = 13100021214093 and 13100021214102.

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 46632387 + ... + 46912466.

Almost surely, 213100021214120 is an apocalyptic number.

13100021214120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13100021214120 is an abundant number, since it is smaller than the sum of its proper divisors (29584495666080).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13100021214120 is a wasteful number, since it uses less digits than its factorization.

13100021214120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 93545259 (or 93545252 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 13100021214120 its reverse (2141212000131), we get a palindrome (15241233214251).

The spelling of 13100021214120 in words is "thirteen trillion, one hundred billion, twenty-one million, two hundred fourteen thousand, one hundred twenty".

Divisors: 1 2 3 4 5 6 8 9 10 12 15 18 20 24 30 36 40 45 60 72 90 120 180 360 389 778 1167 1556 1945 2334 3112 3501 3890 4668 5835 7002 7780 9336 11670 14004 15560 17505 23340 28008 35010 46680 70020 140040 93544853 187089706 280634559 374179412 467724265 561269118 748358824 841903677 935448530 1122538236 1403172795 1683807354 1870897060 2245076472 2806345590 3367614708 3741794120 4209518385 5612691180 6735229416 8419036770 11225382360 16838073540 33676147080 36388947817 72777895634 109166843451 145555791268 181944739085 218333686902 291111582536 327500530353 363889478170 436667373804 545834217255 655001060706 727778956340 873334747608 1091668434510 1310002121412 1455557912680 1637502651765 2183336869020 2620004242824 3275005303530 4366673738040 6550010607060 13100021214120