131000230000 has 50 divisors (see below), whose sum is σ = 317164681064. Its totient is φ = 52400088000.

The previous prime is 131000229967. The next prime is 131000230003. The reversal of 131000230000 is 32000131.

It is a tau number, because it is divible by the number of its divisors (50).

It is a super-3 number, since 3×131000230000³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (10).

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131000230003) by changing a digit.

It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 6540012 + ... + 6560011.

Almost surely, 2^131000230000 is an apocalyptic number.

131000230000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131000230000 is an abundant number, since it is smaller than the sum of its proper divisors (186164451064).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131000230000 is an equidigital number, since it uses as much as digits as its factorization.

131000230000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13100051 (or 13100030 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 10.

Adding to 131000230000 its reverse (32000131), we get a palindrome (131032230131).

The spelling of 131000230000 in words is "one hundred thirty-one billion, two hundred thirty thousand".