Base | Representation |
---|---|
bin | 10011000100000100100… |
… | …111010010011010110000 |
3 | 11122020110002221220202112 |
4 | 103010010213102122300 |
5 | 132430431330330300 |
6 | 2441454123504452 |
7 | 163435033644314 |
oct | 23040447223260 |
9 | 4566402856675 |
10 | 1310042433200 |
11 | 465649889966 |
12 | 191a8a688128 |
13 | 966c8820ac7 |
14 | 475991d5b44 |
15 | 241258b5e35 |
hex | 131049d26b0 |
1310042433200 has 90 divisors (see below), whose sum is σ = 3343407638796. Its totient is φ = 493192401920.
The previous prime is 1310042433187. The next prime is 1310042433211. The reversal of 1310042433200 is 23342400131.
It is a super-2 number, since 2×13100424332002 (a number of 25 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 17 ways as a sum of consecutive naturals, for example, 5550674 + ... + 5781873.
Almost surely, 21310042433200 is an apocalyptic number.
1310042433200 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1310042433200 is an abundant number, since it is smaller than the sum of its proper divisors (2033365205596).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310042433200 is a wasteful number, since it uses less digits than its factorization.
1310042433200 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11332599 (or 11332571 counting only the distinct ones).
The product of its (nonzero) digits is 1728, while the sum is 23.
Adding to 1310042433200 its reverse (23342400131), we get a palindrome (1333384833331).
The spelling of 1310042433200 in words is "one trillion, three hundred ten billion, forty-two million, four hundred thirty-three thousand, two hundred".
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