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13101004800 = 211395213
BaseRepresentation
bin11000011001110000…
…10111100000000000
31020211000212000000000
430030320113200000
5203312324123200
610004000000000
7642440463162
oct141470274000
936730760000
1013101004800
1156131a28a4
122657600000
13130a2a7960
148c3d3c932
1551a254300
hex30ce17800

13101004800 has 720 divisors, whose sum is σ = 52470938520. Its totient is φ = 3224862720.

The previous prime is 13101004793. The next prime is 13101004859. The reversal of 13101004800 is 840010131.

It is a tau number, because it is divible by the number of its divisors (720).

It is a Harshad number since it is a multiple of its sum of digits (18).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 59 ways as a sum of consecutive naturals, for example, 1007769594 + ... + 1007769606.

Almost surely, 213101004800 is an apocalyptic number.

13101004800 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13101004800, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (26235469260).

13101004800 is an abundant number, since it is smaller than the sum of its proper divisors (39369933720).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13101004800 is an frugal number, since it uses more digits than its factorization.

13101004800 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 72 (or 23 counting only the distinct ones).

The product of its (nonzero) digits is 96, while the sum is 18.

Adding to 13101004800 its reverse (840010131), we get a palindrome (13941014931).

The spelling of 13101004800 in words is "thirteen billion, one hundred one million, four thousand, eight hundred".