131012224204032 has 54 divisors (see below), whose sum is σ = 377740540539362. Its totient is φ = 43670741400576.

The previous prime is 131012224203979. The next prime is 131012224204091. The reversal of 131012224204032 is 230402422210131.

131012224204032 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 12 + 2 + 242 + 0 + 403 + 2 = 666.

It can be written as a sum of positive squares in only one way, i.e., 112024104212736 + 18988119991296 = 10584144^2 + 4357536^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131012224203987 and 131012224204005.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 28431469963 + ... + 28431474570.

Almost surely, 2^{131012224204032} is an apocalyptic number.

131012224204032 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

131012224204032 is an abundant number, since it is smaller than the sum of its proper divisors (246728316335330).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131012224204032 is an equidigital number, since it uses as much as digits as its factorization.

131012224204032 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 56862944555 (or 56862944538 counting only the distinct ones).

The product of its (nonzero) digits is 4608, while the sum is 27.

Adding to 131012224204032 its reverse (230402422210131), we get a palindrome (361414646414163).

The spelling of 131012224204032 in words is "one hundred thirty-one trillion, twelve billion, two hundred twenty-four million, two hundred four thousand, thirty-two".