Base | Representation |
---|---|
bin | 11000011001111000… |
… | …01101001011110000 |
3 | 1020211002202010102010 |
4 | 30030330031023300 |
5 | 203313103323440 |
6 | 10004033322520 |
7 | 642452154102 |
oct | 141474151360 |
9 | 36732663363 |
10 | 13102011120 |
11 | 561381a970 |
12 | 2657a06440 |
13 | 130a56aa03 |
14 | 8c4121572 |
15 | 51a3a2580 |
hex | 30cf0d2f0 |
13102011120 has 160 divisors (see below), whose sum is σ = 45738215424. Its totient is φ = 3073766400.
The previous prime is 13102011103. The next prime is 13102011137. The reversal of 13102011120 is 2111020131.
It is an interprime number because it is at equal distance from previous prime (13102011103) and next prime (13102011137).
It is a Harshad number since it is a multiple of its sum of digits (12).
It is a junction number, because it is equal to n+sod(n) for n = 13102011096 and 13102011105.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 1794 + ... + 161886.
Almost surely, 213102011120 is an apocalyptic number.
13102011120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 13102011120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (22869107712).
13102011120 is an abundant number, since it is smaller than the sum of its proper divisors (32636204304).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13102011120 is a wasteful number, since it uses less digits than its factorization.
13102011120 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 160151 (or 160145 counting only the distinct ones).
The product of its (nonzero) digits is 12, while the sum is 12.
Adding to 13102011120 its reverse (2111020131), we get a palindrome (15213031251).
It can be divided in two parts, 131020111 and 20, that added together give a palindrome (131020131).
The spelling of 13102011120 in words is "thirteen billion, one hundred two million, eleven thousand, one hundred twenty".
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