Base | Representation |
---|---|
bin | 10011000100111101101… |
… | …010001110010010000000 |
3 | 11122022220210212011002012 |
4 | 103010331222032102000 |
5 | 132434411333112000 |
6 | 2442133113112052 |
7 | 163500534630224 |
oct | 23047552162200 |
9 | 4568823764065 |
10 | 1310999504000 |
11 | 465aa005136a |
12 | 1920b70b8628 |
13 | 9681bbaa0a4 |
14 | 4764a36a784 |
15 | 2417e917735 |
hex | 1313da8e480 |
1310999504000 has 64 divisors (see below), whose sum is σ = 3259472556600. Its totient is φ = 524399795200.
The previous prime is 1310999503981. The next prime is 1310999504039. The reversal of 1310999504000 is 4059990131.
It can be written as a sum of positive squares in 4 ways, for example, as 860694085696 + 450305418304 = 927736^2 + 671048^2 .
It is a tau number, because it is divible by the number of its divisors (64).
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 40952735 + ... + 40984734.
Almost surely, 21310999504000 is an apocalyptic number.
1310999504000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1310999504000 is an abundant number, since it is smaller than the sum of its proper divisors (1948473052600).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1310999504000 is an frugal number, since it uses more digits than its factorization.
1310999504000 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 81937498 (or 81937476 counting only the distinct ones).
The product of its (nonzero) digits is 43740, while the sum is 41.
The spelling of 1310999504000 in words is "one trillion, three hundred ten billion, nine hundred ninety-nine million, five hundred four thousand".
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