1311130643420 has 48 divisors (see below), whose sum is σ = 3000897396000. Its totient is φ = 478277120256.

The previous prime is 1311130643401. The next prime is 1311130643441. The reversal of 1311130643420 is 243460311131.

It is a happy number.

It is a super-2 number, since 2×1311130643420² (a number of 25 digits) contains 22 as substring.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 30356795 + ... + 30399954.

It is an arithmetic number, because the mean of its divisors is an integer number (62518695750).

Almost surely, 2^{1311130643420} is an apocalyptic number.

1311130643420 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

1311130643420 is an abundant number, since it is smaller than the sum of its proper divisors (1689766752580).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

1311130643420 is a wasteful number, since it uses less digits than its factorization.

1311130643420 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60756854 (or 60756852 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 29.

Adding to 1311130643420 its reverse (243460311131), we get a palindrome (1554590954551).

The spelling of 1311130643420 in words is "one trillion, three hundred eleven billion, one hundred thirty million, six hundred forty-three thousand, four hundred twenty".