1311131000223 has 24 divisors (see below), whose sum is σ = 2121863115216. Its totient is φ = 773148499200.

The previous prime is 1311131000147. The next prime is 1311131000243. The reversal of 1311131000223 is 3220001311131.

1311131000223 is a `hidden beast` number, since 1 + 311 + 131 + 0 + 0 + 0 + 223 = 666.

It is not a de Polignac number, because 1311131000223 - 2¹⁴ = 1311130983839 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1311131000196 and 1311131000205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311131000243) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 178965898 + ... + 178973223.

It is an arithmetic number, because the mean of its divisors is an integer number (88410963134).

Almost surely, 2^{1311131000223} is an apocalyptic number.

1311131000223 is a deficient number, since it is larger than the sum of its proper divisors (810732114993).

1311131000223 is a wasteful number, since it uses less digits than its factorization.

1311131000223 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 357939175 (or 357939172 counting only the distinct ones).

The product of its (nonzero) digits is 108, while the sum is 18.

Adding to 1311131000223 its reverse (3220001311131), we get a palindrome (4531132311354).

The spelling of 1311131000223 in words is "one trillion, three hundred eleven billion, one hundred thirty-one million, two hundred twenty-three", and thus it is an aban number.