Base | Representation |
---|---|
bin | 10011000101000101011… |
… | …111110101110110001101 |
3 | 11122100020222021211222000 |
4 | 103011011133311312031 |
5 | 132440144014001310 |
6 | 2442154131342513 |
7 | 163504022422125 |
oct | 23050537656615 |
9 | 4570228254860 |
10 | 1311131000205 |
11 | 4660582a5414 |
12 | 192133151a39 |
13 | 968401ca8b0 |
14 | 4765d9d9c85 |
15 | 2418b23e4c0 |
hex | 131457f5d8d |
1311131000205 has 32 divisors (see below), whose sum is σ = 2510199525120. Its totient is φ = 645479876160.
The previous prime is 1311131000147. The next prime is 1311131000243. The reversal of 1311131000205 is 5020001311131.
It is not a de Polignac number, because 1311131000205 - 29 = 1311130999693 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 373539841 + ... + 373543350.
It is an arithmetic number, because the mean of its divisors is an integer number (78443735160).
Almost surely, 21311131000205 is an apocalyptic number.
1311131000205 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
It is an amenable number.
1311131000205 is a deficient number, since it is larger than the sum of its proper divisors (1199068524915).
1311131000205 is a wasteful number, since it uses less digits than its factorization.
1311131000205 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 747083218 (or 747083212 counting only the distinct ones).
The product of its (nonzero) digits is 90, while the sum is 18.
Adding to 1311131000205 its reverse (5020001311131), we get a palindrome (6331132311336).
The spelling of 1311131000205 in words is "one trillion, three hundred eleven billion, one hundred thirty-one million, two hundred five", and thus it is an aban number.
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