Base | Representation |
---|---|
bin | 10011000101000101101… |
… | …100110100011101100000 |
3 | 11122100021012200200220020 |
4 | 103011011230310131200 |
5 | 132440200401334100 |
6 | 2442154332313440 |
7 | 163504063352064 |
oct | 23050554643540 |
9 | 4570235620806 |
10 | 1311134402400 |
11 | 46605a209549 |
12 | 192134312880 |
13 | 96840b1c324 |
14 | 47660243aa4 |
15 | 2418b6b25a0 |
hex | 13145b34760 |
1311134402400 has 144 divisors (see below), whose sum is σ = 4298446756800. Its totient is φ = 347120386560.
The previous prime is 1311134402387. The next prime is 1311134402453. The reversal of 1311134402400 is 42044311131.
It is a super-3 number, since 3×13111344024003 (a number of 37 digits) contains 333 as substring.
It is a Harshad number since it is a multiple of its sum of digits (24).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 1631530 + ... + 2298729.
It is an arithmetic number, because the mean of its divisors is an integer number (29850324700).
Almost surely, 21311134402400 is an apocalyptic number.
1311134402400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
1311134402400 is an abundant number, since it is smaller than the sum of its proper divisors (2987312354400).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
1311134402400 is a wasteful number, since it uses less digits than its factorization.
1311134402400 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3930421 (or 3930408 counting only the distinct ones).
The product of its (nonzero) digits is 1152, while the sum is 24.
Adding to 1311134402400 its reverse (42044311131), we get a palindrome (1353178713531).
The spelling of 1311134402400 in words is "one trillion, three hundred eleven billion, one hundred thirty-four million, four hundred two thousand, four hundred".
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